A homologous series of a type of hydrocarbon is given in the table alongside. Where, X and Y are given in serial number 2 and 3 instead of the real compounds.
- Write molecular structure of the compound formed when one hydrogen atom of X is displaced by -OH.
- Write the structural formula of the compound formed by the removal of one hydrogen atom from two adjacent carbon atoms of Y.
| S.N | Homologous series |
| 1. | CH$_4$ |
| 2. | X |
| 3. | Y |
| 4. | CH$_3$CH$_2$CH$_2$CH$_3$ |
Arpit Sundas
·
1 year ago
Solution
Given homologous is series is of alkanes. So, the compounds X and Y must be ethane ( \(\rm C_{2}H_{6}\) ) and propane ( \(\rm C_{3}H_{8}\) )
1)Ans:
Here, X originally is ethane ( \(\rm C_{2}H_{6}\) ).
When one hydrogen atom is displaced by -OH ethane forms ethyl alcohol or ethanol and its molecular structure is ( \(\rm C_{2}H_{5}OH\) ) .Its strucutral formula is:
2) Ans:
Y is propane ( \(\rm C_{3}H_{8}\) ).
The compound formed by removal of one hydrogen atom from two adjacent carbon atoms is propene( \(\rm C_{2}H_{6}\) ). It is done by the process of dehydrogenation (conversion of alkane into an alkene). Its structural formula is:
