Ten > Sequence and Series
Find the geometric mean between: 256 and 64.
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Solution
If the two numbers are a and b, then the geometric mean between them is given by $\rm GM = \sqrt{ab}$.
Given,
$\rm a = 256$ and $\rm b = 64$
By substituting the values into the formula, we get,
$\rm or, GM = \sqrt{ab}$
$\rm or, GM = \sqrt{ 256 \cdot 64 }$
$\rm or, GM = \sqrt{16384}$
$\rm or, GM = \sqrt{ 128^{2} }$
$\rm \therefore GM = 128$
Hence, the required geometric mean between the numbers $\rm 256$ and $\rm 64$ is $\rm 128$.
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