Ten > Sequence and Series
If the geometric mean between two numbers is 27 and the first number is 81, find the second number.
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Solution
If the two numbers are a and b, then the geometric mean between them is given by $\rm GM = \sqrt{ab}$.
Given,
$\rm a = 81$
$\rm GM = 27$
By substituting the values into the formula, we get,
$\rm or, GM = \sqrt{ab}$
$\rm or, GM^{2} = ab$
$\rm or, b = \frac{GM^{2}}{a}$
$\rm or, b = \frac{ 27^{2}}{81}$
$\rm \therefore b = 9$
Hence, the required second number is 9.
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