Ten > Sequence and Series
Asked by Basanta · 2 years ago

If the geometric mean between two numbers is 27 and the first number is 81, find the second number.

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Atith Adhikari Atith Adhikari · 2 years ago
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Solution

If the two numbers are a and b, then the geometric mean between them is given by $\rm GM = \sqrt{ab}$.

Given,

$\rm a = 81$

$\rm GM = 27$

By substituting the values into the formula, we get,

$\rm or, GM = \sqrt{ab}$

$\rm or, GM^{2} = ab$

$\rm or, b = \frac{GM^{2}}{a}$

$\rm or, b = \frac{ 27^{2}}{81}$

$\rm \therefore b = 9$

Hence, the required second number is 9.

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