Solution:

Given,

Mass of Jupiter ( \(\rm m_{j}\) ) = \(\rm 1.9×10^{30} kg\) 

Mass of Sun ( \(\rm m_{s}\) ) = \(\rm 2×10^{30} kg\) 

Gravitational force between them  ( \(\rm F\) ) = \(\rm 4.3×10^{29} N\) 

Universal gravitational constant ( \(\rm G\) )  =  \(\rm 6.67×10^{-11} Nm^{2}kg{-2}\) 

Distance between them  ( \(\rm d\) )   = ?

We know,

 \(\rm F\)=  $ \frac{Gm_1m_2}{d^2} $

\(\rm d^{2}\)=  $ \frac{Gm_jm_s}{F} $

\(\rm d^{2}\)=  $ \frac{6.67×10^{-11}×1.9×10^{30}×2×10^{30}}{4.3×10^{29}} $

\(\rm d\) = \(\rm 2.43×10^{10}\)

Hence, If mass of Jupiter is \(\rm 1.9×10^{30} kg\) , mass of the Sun is\(\rm 2×10^{30} kg\)  and gravitational force between them is \(\rm 4.3×10^{29} N\)  the distance between them is \(\rm 2.43×10^{10}\).