Ten > Pressure
Pressure of 30000 Pa is generated in the liquid of a hydraulic lift. If the cross-sectional area of the piston used to lift a weight is 0.1 m^2, how much load can it lift?
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Solution
Given
Pressure (P) = 30 000 $\rm Pa$
Area (A) = 0.1 $\rm m^2$
To find: Force (F) = ? $\rm N$
By the Pressure Formula, we have,
$\rm P = \frac{F}{A}$
$\rm or, F = P \cdot A$
$\rm or, F = 30 000 \cdot 0.1$
$\rm \therefore F = 3 000 N$
Hence, the given hydraulic lift can lift a maximum load of 3,000 N.
Reason
A hydraulic lift is based on Pascal's law. According to this law, liquid enclosed in a container exerts equal pressure in all directions.
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