Class 12 Periodic Motion Exercise 2 Solutions | Principles of Physics Ayam Publication and Distributors Pvt. Ltd.

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Class 12 Periodic Motion Exercise 2 Solutions | Principles of Physics Ayam Publication and Distributors Pvt. Ltd.

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A simple pendulum is executing simple harmonic motion with a time period T. If the length of the pendulum is increased by 21%, the increase in the time period is

Two springs A and B ($K_A = 3K_B$) are stretched by the same suspended weight. Then the ratio of work done in stretching is

In a simple harmonic motion, if the displacement is half of the amplitude, then which part of total energy will be kinetic energy?

A particle of mass 10g is executing S.H.M. with an amplitude of 0.5m and periodic time of $\frac {\pi}{5}$ seconds. The maximum value of force acting on the particle is

A system exhibiting SHM must possess

How will the period of oscillation of simple pendulum be affected if it is moved from the surface of earth to a mine?

A particle executes SHM with a period 6 sec. and amplitude 0.03m. Its maximum speed in cm/sec is

Two simple pendulum of time period 2.0 sec and 2.1 sec are made to vibrate simultaneously. They are in phase initially. After how many vibrations they are in same phase?

A mass m is vertically suspended from a spring of negligible mass and system frequency n. What will be the frequency of the system, if a mass 4 m is suspended from the same spring?

A particle execute S.H.M with a time period of 2 sec and amplitude 5 cm. Maximum magnitude of its velocity is

A disc of mass m and radius R is attached to the massless rod as shown in Fig.. The period of oscillation of the pendulum is:

A point particle of mass 0.1 kg is executing SHM of amplitude of 0.1m. When the particle passes through the mean position, its kinetic energy is 18 $\times 10^{-3} $ J. The equation of motion of this particle when the initial phase of oscillation is 45$^o$ can be given by

A body executes simple harmonic. The potential energy (P.E), the kinetic energy (K.E) and the total energy (T.E) are measured as a function of displacement x. which of the following statements is true?

The following Fig. depicts a circular motion. The radius of the circle , the period of revolution, the initial position and the sense of revolution are indicated on the figure. The simple harmonic motion of the x$-$projection of the radius vector of the rotating particle P can be shown as:

Two oscillating systems; a simple pendulum and a vertical spring-mass-system have same time period of motion on the surface of the earth. If both are taken to the moon, then-

A simple pendulum with length L and mass M of the bob is vibrating with amplitude a. Then the maximum tension in the string is:

The x-t graph of a particle undergoing simple motion is shown below. The acceleration of the part t=4/3 s is-

The motion of a particle is expressed by the equation $a = - bx$, where x is the displacement from the mean position, a is the acceleration and b is a constant. The periodic time is

The kinetic energy of a particle, executing SHM, is 16 J when it is at its mean position. If the amplitude of oscillations is 25cm, and the mass of the particle is 5.12 kg, the time period of its oscillation is

The length of a simple pendulum executing simple harmonic motion is increased by $ 21 \%$. The percentage increase in the time period of the pendulum is

The maximum velocity of a simple harmonic motion represented by $\rm y= 3\sin ( 100 \pi t + \frac {\pi}{6}) $ is given by

When a particle executing SHM passes through the mean position, it has

If a hole is bored along a diameter of the earth and a stone is dropped into the hole, it will

A body of mass 5 g is executing SHM with amplitude 10 cm. It maximum velocity is 100 cm/s. Its velocity will be 50 cm/s at a displacement from the mean position equal to:

A particle is executing SHM. Then the graph of velocity as a function of displacement is:

The mass and diameter of a planet are twice those of the earth. The time period of a simple pendulum on this planet, if it is a second's pendulum on earth, is:

A pendulum clock, which keeps correct time at sea level, loses 15 s per day when taken to the top of a mountain. If the radius of the earth is 6400 km, the height of the mountain is:

The total energy of a particle executing SHM is proportional to the

A simple pendulum is taken from the equator to a pole. Its period

Resonance is a special case of

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. the frequency of its oscillation is: