If f(x) = 2x + 1 and g(x) = x$\rm{^2}$, then f$\rm\circ$g(3) is equal to:

A function is defined by f(x) = $\rm\frac{3x^{2}+2x-1}{x+1}$ where, x $\rm\in $ R, and x $\rm\neq$  -1. Then the value of $\rm\frac{f(2)}{f(-3)}$ +1 will be:

Let f: R $\rm\to$ R be defined by f(x) = (2x - 1), then (f - 3)x =

If a function f: R $\rm\to $ [-1, 1] is defined by f(x) = Cosx, then the function f is:

The function f: R $\rm\to$ R defined by f(x) = x$\rm{^2}$ is: