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A cell has an emf of 1.5 V. When short circuited, it gives a current of 3 A. The internal resistance of the cell is
In the given circuit current $\rm I_1$ and $\rm I_2$ are:
Four resistors P, Q, R and S, having resistance 2, 2, 2 and 3 $\rm \Omega $ respectively, are arranged to form a wheatstone bridge. The value of the resistance with which S must be shunted in order to balance the bridge is
A 2.0 V potentiometer is used to determine the internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 75 cm. When a resistor of 10 $\Omega$ is connected across the cell, the balance point shifts to 60 cm. The internal resistance of the cell is :
A potentiometer wire is 10 m long and has a resistance of $\rm 20 \;\Omega $. It is connected in series with a battery of emf 3 V and a resistance of $ \rm 10 \Omega $. The potential gradient along the wire in V/m is :
Kirchhoff's second law is based on the law of conservation of:
Using the forumlae $\rm \vec{F} = q \vec{V} \times \vec{B}$ and $\rm B = \frac{\mu_{o} i}{2 \pi r}$, show that the SI units of the magnetic field B and the permeability constant $\rm \mu_{o}$ may be written as $\rm NmA^{-1}$ and $\rm NA^{-2}$ respectively.
A current of 10 A is established in a long wire along the positive z-axis. Find the magnetic field $\rm \vec{B}$ at the point (1m, 0, 0).
A copper wire of diameter 1.6 mm carries a current of 20 A. Find the maximum magnitude of the magnetic field $\rm \vec{B}$ due to this current.
A transmission wire carries a current of 100 A. What would be the magnetic field B at a point on the road if the wire is 8m above the road?
A long, straight wire carrying a current of 1.0 A is placed horizontally in a uniform magnetic field B = $\rm 1.0 \times 10^{-5}$ T pointing vertically upward (figure 35-E1). Find the magnitude of the resultant magnetic field at the points P and Q, both situated at a distance of 2.0 cm from the wire in the same horizontal plane.
Kirchoff's second law is based on the law of conservation of
A potentiometer wire of length 10 m and resistance 30 $\rm \Omega$ is connected in series with a battery of emf 2.5 V with internal resistance 5 $\rm \Omega$ and an external resistance R. If the fall of potential along the potentiometer wire is 50 mV/m, the value of R is (in $\rm \Omega$)
Electromotive force is most closely related to
Potentiometer measures potential more accurately because
A car battery has e.m.f. 12 V and internal resistance $\rm 5\; $x$\; 10^{-2}\; \Omega $. If it draws 60 A current, the terminal voltage of the battery will be
An ammeter and a voltmeter of resistance R are connected in series to an electric cell of negligible internal resistance. Their reading are A and V respectively. If another resistance R is connected in parallel with the voltmeter.
In a typical Wheatstone network, the resistance in cyclic order are P = 10 $\Omega$, Q = 5 $\Omega$, S = 4 $\Omega$, and R = 4 $\Omega$. For the bridge to balance
A battery is connected in series with a resistance R and a voltmeter. An ammeter is a connected in parallel with the battery.
A milliammeter of range 10 mA has a coil of resistance 1 $\Omega$. To use it as a voltmeter of range 10 V, the resistance that must be connected in series with it is
A battery of emf 10 V and internal resistance 3 $\Omega$ is connected to a resistor. The current in the circuit is 0.5 A. The terminal voltage of the battery when the circuit is closed is
A voltmeter having a resistance of $\rm 50\;$x$\;10^3 \;\Omega$ is used to measure the voltage in a circuit. To increase the range of measurement 3 times the additional series resistance required is:
To send 10% of the main current through a moving coil galvanometer of resistance 99 $\rm \Omega$, the shunt required is
For resistances of 100 $\Omega$ each are connected in the form of a square. Then the equivalent resistance between the diagonally opposite points is:
When a resistance of 2 ohm is connected across the terminals of a cell, the current is 0.5 A. When the resistance is increased to 5 ohm, the current is 0.25 A. The e.m.f of the cell is:
A potentiometer wire of length 1 m and resistance 10 $\rm \Omega$ is connected in series with a cell of e.m.f. 2 V and internal resistance 1 $\rm \Omega$ and a resistance box including a resistance R. If the potential different between the ends of the wire is 1 m V, the value of R is
A potentiometer is more sensitive than a voltmeter because
Three resistances of values 2 $\rm \Omega$, 3 $\rm \Omega$, and 6 $\rm \Omega$ are to be connected to produce an effective resistance of 4 $\rm \Omega$. This can be done by connecting
In a meter bridge with standard resistance of 5 $\rm \Omega$ in the left gap, the ratio of balancing lengths of the bridge wire is 2:3. The unknown resistance is
In a meter bridge, a 30 $\rm \Omega$ resistance is connected in the left gap and a pair of resistances P and Q in the right gap. Measured from the left, the balance point is 37.5 cm when P and Q are in series and 71.4 cm when they are parallel. The values of P and Q (in $\rm \Omega$) are
In the circuit shown the value of I in ampere is
Shown in the figure below is a meter bridge set up with a null deflection in the galvanometer. The value of the unknown resistance R is
A meter bridge is set up as shown, to determine an unknown resistance X using standard 10 $\rm \Omega$ resistor. The galvanometer shows null point when tapping key is at 52 cm mark. The end corrections are 1 cm and 2 cm respectively, for the ends A and B. The determined value of X is
Two batteries of different e.m.f.s and different internal resistances are connected as shown. The voltage across AB in volts is
Figure shows a part of a closed electrical circuit. Then V$_A$ - V$_B$ is
A resistance of 5 $\rm \Omega$ is connected in the left gap of a meter bridge and 15 $\rm \Omega$ in the other gap. The position of the balancing point is
In a potentiometer experiment, it is found that no current flows through the galvanometer when the terminals of the cell are connected across 125 cm of the potentiometer wire. On shunting the cell by 2 $\rm \Omega$ resistor, the balancing length is reduced to half. The internal resistance of the cell is
An e.m.f. of 0.9 V is generated when the temperature difference between hot and cold junctions of a thermocouple is 75 $^{\circ}$C. Assuming that cold junction is heated by 15 $^{\circ}$C, the extent to which thermo e.m.f. will change is
The resistivity of a potentiometer wire is 40 x 10$\rm ^{-8}$ ohm-m and its area of cross section is 8 x 10$\rm ^{-6}$ m$^2$. If 0.2 ampere current is flowing through the wire, the potential gradient will be
A potentiometer consists of a wire of length 400 cm and of resistance 10 $\rm \Omega$. It is connected to a cell of e.m.f 2 volt having negligible internal resistance. Calculate the potential difference per unit length of the wire.
In figure, a current 1.4 amp flows towards the bridge circuit. the current in 2 $\rm \Omega$ resistor is
Two cells of 1.25 V and 0.75 V are connected in parallel. The effective voltage will be
The instrument for the accurate measurement of the e.m.f. of a cell is
It is observed in a potentiometer experiment that no current passes through the galvanometer, when the terminals of the cell are connected across a certain length of the potentiometer wire. On shunting the cell by a 2 $\rm \Omega$ resistance, the balancing length is reduced to half. The internal resistance of the cell is
State the principle of the Potentiometer.
A potentiometer is also called a voltmeter of infinite resistance, why?
State the two Kirchoff's laws for electrical circuits.
A cell has an emf of 1.5 V. When short circuited, it gives a current of 3 A. The internal resistance of the cell is
In the given circuit current $\rm I_1$ and $\rm I_2$ are:
Four resistors P, Q, R and S, having resistance 2, 2, 2 and 3 $\rm \Omega $ respectively, are arranged to form a wheatstone bridge. The value of the resistance with which S must be shunted in order to balance the bridge is
A 2.0 V potentiometer is used to determine the internal resistance of a 1.5 V cell. The balance point of the cell in open circuit is 75 cm. When a resistor of 10 $\Omega$ is connected across the cell, the balance point shifts to 60 cm. The internal resistance of the cell is :
A potentiometer wire is 10 m long and has a resistance of $\rm 20 \;\Omega $. It is connected in series with a battery of emf 3 V and a resistance of $ \rm 10 \Omega $. The potential gradient along the wire in V/m is :
Kirchhoff's second law is based on the law of conservation of:
Using the forumlae $\rm \vec{F} = q \vec{V} \times \vec{B}$ and $\rm B = \frac{\mu_{o} i}{2 \pi r}$, show that the SI units of the magnetic field B and the permeability constant $\rm \mu_{o}$ may be written as $\rm NmA^{-1}$ and $\rm NA^{-2}$ respectively.
A current of 10 A is established in a long wire along the positive z-axis. Find the magnetic field $\rm \vec{B}$ at the point (1m, 0, 0).
A copper wire of diameter 1.6 mm carries a current of 20 A. Find the maximum magnitude of the magnetic field $\rm \vec{B}$ due to this current.
A transmission wire carries a current of 100 A. What would be the magnetic field B at a point on the road if the wire is 8m above the road?
A long, straight wire carrying a current of 1.0 A is placed horizontally in a uniform magnetic field B = $\rm 1.0 \times 10^{-5}$ T pointing vertically upward (figure 35-E1). Find the magnitude of the resultant magnetic field at the points P and Q, both situated at a distance of 2.0 cm from the wire in the same horizontal plane.
Kirchoff's second law is based on the law of conservation of
A potentiometer wire of length 10 m and resistance 30 $\rm \Omega$ is connected in series with a battery of emf 2.5 V with internal resistance 5 $\rm \Omega$ and an external resistance R. If the fall of potential along the potentiometer wire is 50 mV/m, the value of R is (in $\rm \Omega$)
Electromotive force is most closely related to
Potentiometer measures potential more accurately because
A car battery has e.m.f. 12 V and internal resistance $\rm 5\; $x$\; 10^{-2}\; \Omega $. If it draws 60 A current, the terminal voltage of the battery will be
An ammeter and a voltmeter of resistance R are connected in series to an electric cell of negligible internal resistance. Their reading are A and V respectively. If another resistance R is connected in parallel with the voltmeter.
In a typical Wheatstone network, the resistance in cyclic order are P = 10 $\Omega$, Q = 5 $\Omega$, S = 4 $\Omega$, and R = 4 $\Omega$. For the bridge to balance
A battery is connected in series with a resistance R and a voltmeter. An ammeter is a connected in parallel with the battery.
A milliammeter of range 10 mA has a coil of resistance 1 $\Omega$. To use it as a voltmeter of range 10 V, the resistance that must be connected in series with it is
A battery of emf 10 V and internal resistance 3 $\Omega$ is connected to a resistor. The current in the circuit is 0.5 A. The terminal voltage of the battery when the circuit is closed is
A voltmeter having a resistance of $\rm 50\;$x$\;10^3 \;\Omega$ is used to measure the voltage in a circuit. To increase the range of measurement 3 times the additional series resistance required is:
To send 10% of the main current through a moving coil galvanometer of resistance 99 $\rm \Omega$, the shunt required is
For resistances of 100 $\Omega$ each are connected in the form of a square. Then the equivalent resistance between the diagonally opposite points is:
When a resistance of 2 ohm is connected across the terminals of a cell, the current is 0.5 A. When the resistance is increased to 5 ohm, the current is 0.25 A. The e.m.f of the cell is:
A potentiometer wire of length 1 m and resistance 10 $\rm \Omega$ is connected in series with a cell of e.m.f. 2 V and internal resistance 1 $\rm \Omega$ and a resistance box including a resistance R. If the potential different between the ends of the wire is 1 m V, the value of R is
A potentiometer is more sensitive than a voltmeter because
Three resistances of values 2 $\rm \Omega$, 3 $\rm \Omega$, and 6 $\rm \Omega$ are to be connected to produce an effective resistance of 4 $\rm \Omega$. This can be done by connecting
In a meter bridge with standard resistance of 5 $\rm \Omega$ in the left gap, the ratio of balancing lengths of the bridge wire is 2:3. The unknown resistance is
In a meter bridge, a 30 $\rm \Omega$ resistance is connected in the left gap and a pair of resistances P and Q in the right gap. Measured from the left, the balance point is 37.5 cm when P and Q are in series and 71.4 cm when they are parallel. The values of P and Q (in $\rm \Omega$) are
In the circuit shown the value of I in ampere is
Shown in the figure below is a meter bridge set up with a null deflection in the galvanometer. The value of the unknown resistance R is
A meter bridge is set up as shown, to determine an unknown resistance X using standard 10 $\rm \Omega$ resistor. The galvanometer shows null point when tapping key is at 52 cm mark. The end corrections are 1 cm and 2 cm respectively, for the ends A and B. The determined value of X is
Two batteries of different e.m.f.s and different internal resistances are connected as shown. The voltage across AB in volts is
Figure shows a part of a closed electrical circuit. Then V$_A$ - V$_B$ is
A resistance of 5 $\rm \Omega$ is connected in the left gap of a meter bridge and 15 $\rm \Omega$ in the other gap. The position of the balancing point is
In a potentiometer experiment, it is found that no current flows through the galvanometer when the terminals of the cell are connected across 125 cm of the potentiometer wire. On shunting the cell by 2 $\rm \Omega$ resistor, the balancing length is reduced to half. The internal resistance of the cell is
An e.m.f. of 0.9 V is generated when the temperature difference between hot and cold junctions of a thermocouple is 75 $^{\circ}$C. Assuming that cold junction is heated by 15 $^{\circ}$C, the extent to which thermo e.m.f. will change is
The resistivity of a potentiometer wire is 40 x 10$\rm ^{-8}$ ohm-m and its area of cross section is 8 x 10$\rm ^{-6}$ m$^2$. If 0.2 ampere current is flowing through the wire, the potential gradient will be
A potentiometer consists of a wire of length 400 cm and of resistance 10 $\rm \Omega$. It is connected to a cell of e.m.f 2 volt having negligible internal resistance. Calculate the potential difference per unit length of the wire.
In figure, a current 1.4 amp flows towards the bridge circuit. the current in 2 $\rm \Omega$ resistor is
Two cells of 1.25 V and 0.75 V are connected in parallel. The effective voltage will be
The instrument for the accurate measurement of the e.m.f. of a cell is
It is observed in a potentiometer experiment that no current passes through the galvanometer, when the terminals of the cell are connected across a certain length of the potentiometer wire. On shunting the cell by a 2 $\rm \Omega$ resistance, the balancing length is reduced to half. The internal resistance of the cell is
State the principle of the Potentiometer.
A potentiometer is also called a voltmeter of infinite resistance, why?
State the two Kirchoff's laws for electrical circuits.