Questions

The sum of the numbers is 16 and the sum of their squares is 130.

1. If one number be x then find other number in terms of x.
2. Write an equation to represent "sum of their squares is 130"
3. Find the value of x.
4. What is the difference of their squares?

The sum of two numbers is 21 and the sum of their squares is 261.

1. If one number be x then find other number in terms of x.
2. Write an equation to represent "sum of their squares is 261".
3. Find the value of x.
4. What is the difference of their squares?

One year hence, a father's age will be 5 times as old as his son's age. The product of the present ages of the father and his son is 145.

1. If the age of the son one years hence be ‘x’ years then write the age of the father one year hence in terms of ’x'.
2. Write their present ages in terms of x.
3. Find the value of x.
4. Find their present ages. 
    

6 years ago, a man's age was 6 times the age of his son. The product of the present ages of the father and his son is 396.

1. If the age of the son 6 years ago be ‘y’ years then write the age of the father before 6 years in terms of y.
2. Write the present ages of the man and his son in terms of y.
3. What is the value of y?
4. Find their present ages.

The product of the present ages of two brothers is 160. 4 years ago, the elder brother was two years as old as his younger brother.

1. If the age of the younger brother 4 years ago was 'w' years then write the age of the elder brother 4 years ago.
2. Write the present ages of two brothers in terms of w.
3. Find the value of w.
4. Find their present ages, 
    

The product of the present ages of two sisters is 150. 5 years ago, the elder sister was twice as old as her younger sister.

1. If the age of the younger sister before 5 years be p years then find that of the elder sister in terms of p.
2. Find their present ages in terms of p.
3. Find the value of p.
4. Find the present ages of two sisters.

The sum of the present ages of elder and younger sisters is 28 years and the product of their ages is 187.

1. If the present age of the younger sister is n years then find the present age of the elder sister in terms of n.
2. Find the value of n.
3. Find the present age of the elder sister.
4. What will be the product of their ages after 4 years?

The sum of the present ages of elder and younger brothers is 30 years and the product of their ages is 221.

1. If the present age of the younger be 'a' years then find the ages of the elder brother in terms of a.
2. Find the value of a.
3. Find the present age of the elder brother.
4. What will be the product of their ages after 5 years?

The difference of the present ages of two brothers is 7 years and the product of their ages is 44.

1. If the age of the younger brother be m years then write the age of the elder brother in terms of m.
2. Find the value of m.
3. Find the present age of the elder brother.
4. Find their ages before 3 years.

The difference of the present ages of two sisters is 5 years and the product of their ages is 84.

1. If the age of the younger sister be x years then write the age of elder sister in terms of x.
2. Find the value of x. 
3. Find the present age of the elder sister. 
4. Find their ages after 10 years.